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Flatten subprojects into a single base monorepo
2026-09-02 16:34:47 -07:00

80 lines
2.3 KiB
C++

// clang-format off
// This test verifies correctness of Xteam Reduction when a pointer to a reduction
// variable is passed to a function. Currently, Xteam reduction does not kick in but
// the test executes successfully.
//
// RUN: %libomptarget-compile-generic -fopenmp-target-fast
// RUN: env LIBOMPTARGET_KERNEL_TRACE=1 %libomptarget-run-generic 2>&1 | %fcheck-generic
// UNSUPPORTED: nvptx64-nvidia-cuda
// UNSUPPORTED: nvptx64-nvidia-cuda-LTO
// UNSUPPORTED: aarch64-unknown-linux-gnu
// UNSUPPORTED: aarch64-unknown-linux-gnu-LTO
// UNSUPPORTED: x86_64-unknown-linux-gnu
// UNSUPPORTED: x86_64-unknown-linux-gnu-LTO
// clang-format on
#include <omp.h>
#include <stdio.h>
int compute_sum_res(int j, double *result, double a[]) {
*result += a[j];
return 1;
}
void compute_sum(int j, double *result, double a[]) { *result += a[j]; }
double compute_sum_rval(int j, double rval, double a[]) { return rval + a[j]; }
int foo(int i) { return 2 * i; }
int main() {
int N = 10000;
double a[N];
for (int i = 0; i < N; i++)
a[i] = i;
double sum1, sum2, sum3, sum4, sum5;
sum1 = sum2 = sum3 = sum4 = sum5 = 0;
int res = 0;
#pragma omp target teams distribute parallel for map(tofrom:sum1) reduction(+:sum1) map(tofrom:res)
for (int j = 0; j < N; j = j + 1)
res = compute_sum_res(j, &sum1, a);
#pragma omp target teams distribute parallel for reduction(+ : sum2)
for (int j = 0; j < N; j = j + 1)
compute_sum(j, &sum2, a);
#pragma omp target teams distribute parallel for reduction(+ : sum3)
for (int j = 0; j < N; j = j + 1)
sum3 = compute_sum_rval(j, *&sum3, a);
#pragma omp target teams distribute parallel for reduction(+ : sum4)
for (int j = 0; j < N; j = j + 1)
foo(compute_sum_res(j, &sum4, a));
#pragma omp target teams distribute parallel for reduction(+ : sum5)
for (int j = 0; j < N; j = j + 1)
compute_sum_res(j, &sum5, a);
printf("%f %f %f %f %f\n", sum1, sum2, sum3, sum4, sum5);
int rc = (sum1 != 49995000) || (sum2 != 49995000) || (sum3 != 49995000) ||
(sum4 != 49995000) || (sum5 != 49995000);
if (!rc)
printf("Success\n");
return rc;
}
/// CHECK: DEVID:[[S:[ ]*]][[DEVID:[0-9]+]] SGN:2
/// CHECK: DEVID:[[S:[ ]*]][[DEVID:[0-9]+]] SGN:2
/// CHECK: DEVID:[[S:[ ]*]][[DEVID:[0-9]+]] SGN:2
/// CHECK: DEVID:[[S:[ ]*]][[DEVID:[0-9]+]] SGN:2
/// CHECK: DEVID:[[S:[ ]*]][[DEVID:[0-9]+]] SGN:2