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66 lines
2.1 KiB
C++
66 lines
2.1 KiB
C++
//===----------------------------------------------------------------------===//
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//
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// Part of the LLVM Project, under the Apache License v2.0 with LLVM Exceptions.
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// See https://llvm.org/LICENSE.txt for license information.
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// SPDX-License-Identifier: Apache-2.0 WITH LLVM-exception
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//
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//===----------------------------------------------------------------------===//
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// UNSUPPORTED: c++03, c++11
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#include <algorithm>
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#include <cstddef>
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#include <cstdint>
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#include <iterator>
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#include <vector>
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#include "fuzz.h"
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extern "C" int LLVMFuzzerTestOneInput(const std::uint8_t *data, std::size_t size) {
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auto is_even = [](auto t) {
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return t % 2 == 0;
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};
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std::vector<std::uint8_t> v1, v2;
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auto iter = std::partition_copy(data, data + size,
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std::back_inserter<std::vector<std::uint8_t>>(v1),
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std::back_inserter<std::vector<std::uint8_t>>(v2),
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is_even);
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((void)iter);
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// The two vectors should add up to the original size
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if (v1.size() + v2.size() != size)
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return 1;
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// All of the even values should be in the first vector, and none in the second
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if (!std::all_of(v1.begin(), v1.end(), is_even))
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return 2;
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if (!std::none_of(v2.begin(), v2.end(), is_even))
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return 3;
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// Every value in both vectors has to be in the original
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// Make a copy of the input, and sort it
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std::vector<std::uint8_t> v0{data, data + size};
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std::sort(v0.begin(), v0.end());
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// Sort each vector and ensure that all of the elements appear in the original input
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std::sort(v1.begin(), v1.end());
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if (!std::includes(v0.begin(), v0.end(), v1.begin(), v1.end()))
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return 4;
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std::sort(v2.begin(), v2.end());
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if (!std::includes(v0.begin(), v0.end(), v2.begin(), v2.end()))
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return 5;
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// This, while simple, is really slow - 20 seconds on a 500K element input.
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// for (auto v: v1)
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// if (std::find(data, data + size, v) == data + size)
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// return 4;
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//
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// for (auto v: v2)
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// if (std::find(data, data + size, v) == data + size)
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// return 5;
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return 0;
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}
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